JEE Exam  >  JEE Questions  >  | cos x{sin x +(sin^2x +sin^2y)sqrt} |? Start Learning for Free
| cos x{sin x +(sin^2x +sin^2y)sqrt} |?
Most Upvoted Answer
| cos x{sin x +(sin^2x +sin^2y)sqrt} |?
**Simplifying the Expression | cos x{sin x (sin^2x sin^2y)sqrt} |**

To simplify the given expression, we need to follow the order of operations (PEMDAS/BODMAS) and apply the trigonometric identities.

1. Evaluate the innermost parentheses:
- (sin^2x sin^2y)

This expression represents the product of the squares of the sine values of angles x and y. There are no additional simplifications we can make at this point.

2. Simplify the expression inside the curly braces:
- sin x (sin^2x sin^2y)

We can rewrite this as sin x * sin^2x * sin^2y.

3. Apply the trigonometric identity:
- sin^2θ = (1 - cos 2θ) / 2

We can use this identity to rewrite each sin^2 term in terms of cos 2θ.

4. Substituting the trigonometric identity:
- sin x * [(1 - cos 2x) / 2] * [(1 - cos 2y) / 2]

Now, we have expressed each sin^2 term in terms of cos.

5. Simplify the expression:
- sin x * (1 - cos 2x) * (1 - cos 2y) / 4

We can simplify the expression by multiplying everything together and dividing by 4.

6. Apply the trigonometric identity:
- cos 2θ = 2cos^2θ - 1

We can use this identity to rewrite each cos 2θ term.

7. Substituting the trigonometric identity:
- sin x * (1 - (2cos^2 2x - 1)) * (1 - (2cos^2 2y - 1)) / 4

Now, we have expressed each cos 2θ term in terms of cos.

8. Simplify the expression:
- sin x * (2 - 2cos^2 2x) * (2 - 2cos^2 2y) / 4

We can simplify the expression by expanding and simplifying each binomial term.

9. Apply the trigonometric identity:
- cos^2θ = (1 + cos 2θ) / 2

We can use this identity to rewrite each cos^2 term.

10. Substituting the trigonometric identity:
- sin x * (2 - 2((1 + cos 4x) / 2)) * (2 - 2((1 + cos 4y) / 2)) / 4

Now, we have expressed each cos^2 term in terms of cos.

11. Simplify the expression:
- sin x * (2 - (1 + cos 4x)) * (2 - (1 + cos 4y)) / 4

We can simplify the expression by expanding and simplifying.

12. Simplify further:
- sin x * (1 - cos 4x) * (1 - cos 4y) / 4

We can simplify the expression by multiplying everything together.

13. Simplify the outermost brackets:
- cos x * sin x * (1 -
Explore Courses for JEE exam
| cos x{sin x +(sin^2x +sin^2y)sqrt} |?
Question Description
| cos x{sin x +(sin^2x +sin^2y)sqrt} |? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about | cos x{sin x +(sin^2x +sin^2y)sqrt} |? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for | cos x{sin x +(sin^2x +sin^2y)sqrt} |?.
Solutions for | cos x{sin x +(sin^2x +sin^2y)sqrt} |? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of | cos x{sin x +(sin^2x +sin^2y)sqrt} |? defined & explained in the simplest way possible. Besides giving the explanation of | cos x{sin x +(sin^2x +sin^2y)sqrt} |?, a detailed solution for | cos x{sin x +(sin^2x +sin^2y)sqrt} |? has been provided alongside types of | cos x{sin x +(sin^2x +sin^2y)sqrt} |? theory, EduRev gives you an ample number of questions to practice | cos x{sin x +(sin^2x +sin^2y)sqrt} |? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev